NEET2021ChemistryCoordination CompoundsActual
Match List - I with List - II. List-I List-II (a) Fe ( CN ) 6 3 - (i) 5 . 92   BM (b) Fe H 2 O 6 3 + (ii) 0   BM (c) [ Fe ( CN ) 6 ] 4 - (iii) 4 . 90   BM (d) Fe H 2 O 6 2 + (iv) 1 . 73   BM Choose the correct answer from the options given below.
Options
- A(a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
- B(a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
- C(a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
- D(a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
Correct answer
D. (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
Step-by-step solution
Fe ( CN ) 6 3 - has Fe 3 + central ion d 5 Electronic configuration (SFL) t 2 g e g 2 , 2 , 1 0 , 0 n = 1 Magnetic moment: μ = n n + 2   BM = 1 ( 1 + 2 ) = 3 = 1 . 73   BM Fe H 2 O 6 3 + : has d 5 electrons. Electronic configuration (WFL) t 2 g e 1 , 1 , 1 g 1 , 1 n = 5 μ = 5 ( 5 + 2 ) = 35 = 5 . 92   B . M . Fe ( CN ) 6 4 - has d 6 electrons. Electronic configuration (SFL) t 2 g 2 , 2 , 1 e g 0 , 0 n = 0 μ = 0   B . M . Fe H 2 O 6 2 + has d 6 electron Electronic configuration: (W