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NEET 2013

Exam: NEET
Year: 2013
Subject: Chemistry
Chapter: Coordination Compounds

NEET 2013 · Chemistry · Coordination Compounds

Crystal field spliting energy for high spin d^4 octahedral complex...

Crystal field spliting energy for high spin

d^4

octahedral complex is:

Options

A $-1.2 \Delta_0$
B $-0.6 \Delta_0$
C $-0.8 \Delta_0$
D $-1.6 \Delta_0$

Correct answer

B. $-0.6 \Delta_0$

Step-by-step solution

\mathrm{CFSE}=(-0.4 x+0.6 y) \Delta_0x

is no of

t_{2 \mathrm{~g}}

orbital while

\mathrm{y}

is no of

e_g

orbital

\begin{aligned}& =(-0.4 \times3+0.6 \times1) \Delta_0 \\ & =-0.6 \Delta_0 \end{aligned}

$

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