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NEET2008ChemistryCoordination CompoundsActual

Which of the following complexes exhibits the highest paramagnetic behaviour? where gly = glycine, en = ethylenediamine and bpy = bipyridyl moities (At no: Ti =22, ~V =23, Fe =26, Co =27 )

Options

  1. A[ V ( gly )₂( OH )₂ ( NH ₃ )₂ ]⁺
  2. B[ Fe ( en ) ( bpy) ( NH ₃ )₂ ]²⁺ .
  3. C[ Co ( OX )₂( OH )₂ ]⁻
  4. D[ Ti ( NH ₃ )₆ ]³⁺

Correct answer

C. [ Co ( OX )₂( OH )₂ ]⁻

Step-by-step solution

Key Idea : Greater is the number of unpaired electrons, larger is the paramagnetism. aligned & [ V ( gly )₂( OH )₂ ( NH ₃ )₂ ]⁺ & V ₂₃=[ Ar ] 4 s^2, 3 d^3 aligned Oxidation state of V in [ V ( gly )₂( OH )₂ ( NH ₃ )₂ ]⁺ is gathered x+(-1) 2+(-1) 2+(0) 2=+1 x=+5 ~V ⁵⁺=[ Ar ] 3 d^0 gathered (No unpaired electron in option (A)) So, option (B), aligned & [ Fe ( en) ( bpy ) ( NH ₃ )₂ ]²⁺ . & Fe ₂₆=[ Ar ] 4 s^2, 3 d^6 aligned Oxidation state of Fe in [ Fe ( en ) (bpy) ( NH ₃ )₂ ]²⁺ is gathered x+(0)+(0)+(0) 2=+2 x=+2 Fe

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