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NEET 2006
Exam
NEET
Year
2006
Subject
Chemistry
Chapter
Coordination Compounds

NEET 2006 · Chemistry · Coordination Compounds

[Cr(H_2 O)_6] Cl_3 (at. no. or Cr=24 ) has a magnetic moment of...

[Cr(H2O)6]Cl3\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3 (at. no. or Cr=24\mathrm{Cr}=24 ) has a magnetic moment of 3.83 B.M. The correct distribution of 3d3 d electrons in the Chromium of the complex is:[Cr(H_2 O)_6] Cl_3 (at. no. or Cr=24 ) has a magnetic moment of 3.83 B.M. The correct distribution of 3 d electrons in[Cr(H_2 O)_6] Cl_3 (at. no. or Cr=24 ) has a magnetic moment of 3.83 B.M. The correct distribution of 3 d electrons in

Options

  1. A(\left(3 \mathrm{~d} \mathrm{x}^2-\mathrm{y}^2\right)^1, 3  d\mathrmz21,\mathrm{~d} \mathrmz^{2^1},3 dxz\mathrm{dxz})
  2. B(3 \mathrm{~d} \mathrm{xy}^1,\left(33\mathrm{~d}x^2-y²\right)^1, 3\mathrm{~d}$y z¹)
  3. C(3 \mathrm{~d} x y^1, 3 \mathrm{~d} y z^1, 3 \mathrm{~d} x z^1)
  4. D(3 \mathrm{~d} \mathrm{xy}^1, 3 \mathrm{dyz}{ }^1, 3 d z^{2^{\prime}})

Correct answer

D. (3 \mathrm{~d} \mathrm{xy}^1, 3 \mathrm{dyz}{ }^1, 3 d z^{2^{\prime}})

Step-by-step solution

Magnetic moment (μ)=n(n+2)BM3.83=n(n+2)3.83×3.83=n2+2n14.6689=n2+2n\begin{aligned} (\mu)& =\sqrt{n(n+2)} \mathrm{BM}\\ 3.83 & =\sqrt{n(n+2)}\\ 3.83 \times3.83 & =n²+2 n \\ 14.6689 & =n²+2 n \end{aligned}On solving this, we get n=3n=3. Hence, the number of unpaired electrons in the dd-subshell of the penultimate shell of chromium is 3 . So, Cr3+=1s2,2s22p6,3s23p23d3In[Cr(H2O)6]Cl3\mathrm{Cr}^{3+}=1 s^2, 2 s^2 2 p^6, 3 s^2 3 p^2 3 d^3 In \left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3, the oxidation state of Cr\mathrm{Cr} is +3 . Hence, in 3d33 d^3, the distribution of electrons is $3 d_{x y}^1, 3 d^1, 3 d^1{ }_{x x^*} [Cr(H_2 O)_6] Cl_3 (at. no. or Cr=24 ) has a magnetic moment of 3.83 B.M. The correct distribution of 3 d electrons in
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