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NEET 2002
Exam
NEET
Year
2002
Subject
Chemistry
Chapter
Coordination Compounds

NEET 2002 · Chemistry · Coordination Compounds

Atomic number of Cr and Fe are respectively 24 and 26 , which of...

Atomic number of Cr\mathrm{Cr} and Fe\mathrm{Fe} are respectively 24 and 26 , which of the following is paramagnetic?

Options

  1. A[Cr(CO)6]\left[\mathrm{Cr}(\mathrm{CO})_6\right]
  2. B[Fe(CO)5]\left[\mathrm{Fe}(\mathrm{CO})_5\right]
  3. C[Fe(CN6]4−\left[\mathrm{Fe}\left(\mathrm{CN}_6\right]^{4-}\right.
  4. D\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]^{3+}

Correct answer

D. \left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]^{3+}

Step-by-step solution

Odd electrons, ions and molecules are paramagnetic. In (\mathrm{Cr}(\mathrm{CO})_6) molecule 12 electrons are contributed by CO group and it contains no odd electron. (\mathrm{Cr} \rightarrow 3 d^5 4 s^1) (\mathrm{Fe}(\mathrm{CO})_5) molecule also does not contain odd electron. (Fe→3d64s2In[Fe(CN)6]4 ion Fe(+II)→3d64s0\begin{aligned} & \mathrm{Fe} \rightarrow 3 d^6 4 s^2 \\ & \mathrm{In}\left[\mathrm{Fe}(\mathrm{CN})_6\right]^4 \text{ ion } \mathrm{Fe}(+\mathrm{II}) \rightarrow 3 d^6 4 s^0 \end{aligned}) (\therefore) No odd electrons. (\text{In }\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]^{3+} \text{ ion } \mathrm{Cr}(+III\mathrm{III}) \rightarrow 3 d^3 4 s^0) This ion contains odd electron so it is paramagnetic.
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