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NEET 2023
Exam
NEET
Year
2023
Subject
Chemistry
Chapter
Electrochemistry

NEET 2023 · Chemistry · Electrochemistry

The correct value of cell potential in volt for the reaction that...

The correct value of cell potential in volt for the reaction that occurs when the following two half cells are connected, is Fe(aq)2++2e−→Fe(s),E∘=−0.44 VCr2O72−(aq)+14H++6e−→2Cr3++7H2O,E0=+1.33 V\begin{aligned} & \mathrm{Fe}_{(\mathrm{aq})}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Fe}(\mathrm{s}), \mathrm{E}^{\circ}=-0.44 \mathrm{~V} \\ & \mathrm{Cr}_2 \mathrm{O}_7^{2-}(\mathrm{aq})+14 \mathrm{H}^{+}+6 \mathrm{e}^{-} \rightarrow 2 \mathrm{Cr}^{3+}+7 \mathrm{H}_2 \mathrm{O}, \mathrm{E}^0=+1.33 \mathrm{~V} \\ & \end{aligned}

Options

  1. A+0.01 V+0.01 \mathrm{~V}
  2. B+0.89 V+0.89 \mathrm{~V}
  3. C+1.77 V+1.77 \mathrm{~V}
  4. D+2.65 V+2.65 \mathrm{~V}

Correct answer

C. +1.77 V+1.77 \mathrm{~V}

Step-by-step solution

\begin{aligned} \mathrm{E}_{\text{cell }^0 & =\mathrm{E}_{\text{cathode }}-\mathrm{E}_{\text{anode }} \\ & =1.33-(-0.44) \\ & =1.33+0.44=+1.77 \mathrm{ V}\end{aligned}
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