The E^ values for aligned & Al^ + / Al=+0.55 V and Tl^ + / TI=-0.34 V & Al^ 3+ / Al=-1.66 V and Tl^ 3+ / TI=+1.26 V aligned Identify the incorrect statement.

Correct answer: D. Tl^ 3+ is a good reducing agent than Tl^ 1+ . (1) Al^ + is unstable in solution because SRP of Al^ + / Al is positive hence, it will get reduced in solution. (2) array ll Tl / Tl^ + =+0.34 & (SOP) Tl / Tl^ 3+ =-1.26 & (SOP) array Since, SOP TI/TI > TI/T1 ^ + Hence, TI will get oxidised to Tl^ + easily than Tl^ 3+ (3) Since Al^2 / Al^ 3+ has more SOP than Tl / Tl^ + it will be more electropositive (4) Since aligned Tl^ 3+ +2 e^ - arrow Tl^ + ; E=(3 × 1.26+0.34)/(2) =+2.04 aligned Hence, Tl^ 3+ is better oxidising agent not reducing agent

NEET 2023

Exam: NEET
Year: 2023
Subject: Chemistry
Chapter: Electrochemistry

NEET 2023 · Chemistry · Electrochemistry

The E^ values for aligned & Al^ + / Al=+0.55 V and Tl^ + / TI=-0.34...

The

E^{\ominus}

values for

\begin{aligned} & \mathrm{Al}^{+} / \mathrm{Al}=+0.55 \mathrm{ V} \text{ and } \mathrm{Tl}^{+} / \mathrm{TI}=-0.34 \mathrm{ V} \\ & \mathrm{Al}^{3+} / \mathrm{Al}=-1.66 \mathrm{ V} \text{ and } \mathrm{Tl}^{3+} / \mathrm{TI}=+1.26 \mathrm{ V}\end{aligned}

Identify the incorrect statement.

Options

A $\mathrm{Al}^{+}$ is unstable in solution.
B $\mathrm{TI}$ can be easily oxidised to $\mathrm{Tl}^{+}$ than $\mathrm{Tl}^{3+}$ .
C $\mathrm{Al}$ is more electropositive than $\mathrm{TI}$ .
D $\mathrm{Tl}^{3+}$ is a good reducing agent than $\mathrm{Tl}^{1+}$ .

Correct answer

D. $\mathrm{Tl}^{3+}$ is a good reducing agent than $\mathrm{Tl}^{1+}$ .

Step-by-step solution

(1)

\mathrm{Al}^{+}

is unstable in solution because

\mathrm{SRP} of \mathrm{Al}^{+} / \mathrm{Al}

is positive hence, it will get reduced in solution. (2)

\begin{array}{ll}\mathrm{Tl} / \mathrm{Tl}^{+}=+0.34 & (\mathrm{SOP}) \\ \mathrm{Tl} / \mathrm{Tl}^{3+}=-1.26 & (\mathrm{SOP})\end{array}

Since, SOP TI/TI

>

TI/T1

{ }^{+}

Hence,

\mathrm{TI}

will get oxidised to

\mathrm{Tl}^{+}easily than \mathrm{Tl}^{3+} (3) Since \mathrm{Al}^2 / \mathrm{Al}^{3+}

has more SOP than

\mathrm{Tl}

\mathrm{Tl}^{+}it will be more electropositive (4) Since

\begin{aligned} \mathrm{Tl}^{3+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Tl}^{+} ; \mathrm{E}=\frac{3 \times 1.26+0.34}{2} \\ =+2.04\end{aligned}

Hence, \mathrm{Tl}^{3+}

is better oxidising agent not reducing agent

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