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The conductivity of centimolar solution of KCl at 25 ° C is 0 . 0210   ohm - 1   cm - 1 and the resistance of the cell containing the solution at 25 ° C is 60   ohm . The value of cell constant is

Options

  1. A3 . 34   cm - 1
  2. B1 . 34   cm - 1
  3. C3 . 28   cm - 1
  4. D1 . 26   cm - 1

Correct answer

D. 1 . 26   cm - 1

Step-by-step solution

Conductivity κ = 0 . 0210   ohm - 1 cm - 1 Resistance R = 60   ohm The relation between specific conductance or conductivity and resistance is κ = 1 R l a In the above equation l a is the cell constant. l a = κ × R ⇒ l a = 0 . 0210 × 60 = 1 . 26   cm - 1

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