The conductivity of centimolar solution of KCl at 25 ° C is 0 ....

Conductivity$\left(κ\right) = 0 . 0210{ohm}^{- 1}{cm}^{- 1}$

Resistance\left(R\right) = 60ohm$</p><p>The relation between specific conductance or conductivity and resistance is </p><p>$κ = \dfrac{1}{R}\dfrac{l}{a}$</p><p>In the above equation$\dfrac{l}{a}$is the cell constant.</p><p>$\dfrac{l}{a} = κ \times R$</p><p>$⇒ \dfrac{l}{a} = 0 . 0210 \times 60 = 1 . 26{cm}^{- 1}