NEET2020PhysicsMagnetic Properties of MatterActual
An iron rod of susceptibility 599 is subjected to a magnetising field of 1200   A   m – 1 . The permeability of the material of the rod is: μ 0 = 4 π × 10 − 7   T   m   A − 1
Options
- A8.0 × 10 − 5   T   m   A − 1
- B2.4 π × 10 − 5   T   m   A − 1
- C2.4 π × 10 − 7   T   m   A − 1
- D2.4 π × 10 − 4   T   m   A − 1
Correct answer
D. 2.4 π × 10 − 4   T   m   A − 1
Step-by-step solution
μ r = x m + 1 = 599 + 1 = 600 μ = μ o μ r = 4 π × 10 − 7 × 600 = 2 . 4 π × 10 − 4 Tm A