The magnetic moment and moment of inertia of a magnetic needle as shown are, respectively, $1.0 \times 10^{-2} \mathrm{~A} \mathrm{~m}$ and $\frac{10^{-6}}{\pi^2} \mathrm{~kg} \mathrm{~m}^2$ . If it completes 10 oscillations in 10 s , the magnitude of the magnetic field is

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The magnetic moment and moment of inertia of a magnetic needle as shown are, respectively,

1.0 \times 10^{-2} \mathrm{~A} \mathrm{~m}

and

\frac{10^{-6}}{\pi^2} \mathrm{~kg} \mathrm{~m}^2

. If it completes 10 oscillations in 10 s , the magnitude of the magnetic field is The magnetic moment and moment of inertia of a magnetic needle as shown are, respectively, 1.0 × 10^ -2 ~A ~m and 10^

The magnetic moment and moment of inertia of a magnetic needle as shown are, respectively, 1.0 × 10^ -2 ~A ~m and 10^

Quantrex Academy · Accepted Answer

Correct answer: C. 0.4 mT

Time period of oscillation of magnet inside the magnetic field T=2 π (1)/(M B) T=(t)/(n)=(10)/(10)=1 ~s 1=2 π 10^ -6 π^2 × 1.0 × 10^ -2 × B (1)/(4)= 10^ -4 B B=0.4 mT

The magnetic moment and moment of inertia of a magnetic needle as...

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