NEET2009PhysicsMagnetic Properties of MatterActual
A bar magnet having a magnetic movement of 2 10^4 JT ⁻¹ is free to rotate in a horizontal plane. A horizontal magnetic field B=6 10⁻⁴T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60^ from the field is :
Options
- A2 ~J
- B0.6 ~J
- C12 ~J
- D6 ~J
Correct answer
D. 6 ~J
Step-by-step solution
aligned W & = MB ( ₁- ₂ ) & =2 10^4 6 10⁻⁴ ( - 60^ ) & =12 1 2 =6 ~J aligned