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NEET 2020
Exam
NEET
Year
2020
Subject
Physics
Chapter
Semiconductors

NEET 2020 · Physics · Semiconductors

A n - p - n transistor is connected in common emitter configuration...

A n−p−nn - p - n transistor is connected in common emitter configuration in which collector voltage drop across load resistance (800Ω)( 800Ω ) connected to the collector circuit is 0.8V.0 . 8V . The collector current is

Options

  1. A2mA2mA
  2. B0.1mA0 . 1mA
  3. C1mA1mA
  4. D0.2mA0 . 2mA

Correct answer

C. 1mA1mA

Step-by-step solution

The voltage drop across load resistance=0.8V= 0 . 8V, then from the idea of Ohm's law the current flowing through the collector is,

IC=VCRC=0.8800=10−3A=1mA{I}_{C} = \dfrac{{V}_{C}}{{R}_{C}} = \dfrac{0 . 8}{800} = {10}^{- 3}A = 1mA.

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