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NEET 2016
Exam
NEET
Year
2016
Subject
Physics
Chapter
Semiconductors

NEET 2016 · Physics · Semiconductors

For common emitter transistor amplifier, the audio signal voltage...

For common emitter transistor amplifier, the audio signal voltage across the collector resistance of 2kΩ2kΩ is 4V.4 V. If the current amplification factor of the transistor is 100100 and the base resistance is 1kΩ1kΩ then the input signal voltage is

Options

  1. A10mV10\text{mV}
  2. B20mV20\text{mV}
  3. C30mV30\text{mV}
  4. D15mV15\text{mV}

Correct answer

B. 20mV20\text{mV}

Step-by-step solution

RC=2kΩV0=4V{R}_{C} = 2kΩ{V}_{0} = 4V

IC=V0Rc=4V2kΩ=2mA{I}_{C} = \dfrac{{V}_{0}}{{R}_{c}} = \dfrac{4V}{2kΩ} = 2mA

β=ICIB=100\beta = \dfrac{{I}_{C}}{{I}_{B}} = 100

⇒IB=IC100=2×10−5A⇒ {I}_{B} = \dfrac{{I}_{C}}{100} = 2 \times {10}^{- 5}A

Vin=IBRi=2×10−5×1kΩ=20mV{V}_{in} = {I}_{B}{R}_{i} = 2 \times {10}^{- 5} \times 1kΩ = 20mV
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