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NEET 2016
Exam
NEET
Year
2016
Subject
Physics
Chapter
Semiconductors

NEET 2016 · Physics · Semiconductors

Consider the junction diode as ideal. The value of current flowing...

Consider the junction diode as ideal. The value of current flowing through AB is:
Consider the junction diode as ideal. The value of current flowing through AB is:

Options

  1. A0A\text{0}\text{A}
  2. B10−2A{\text{10}}^{- 2} \text{A}
  3. C10−1A{\text{10}}^{- 1} \text{A}
  4. D10−3A{\text{10}}^{- 3} \text{A}

Correct answer

B. 10−2A{\text{10}}^{- 2} \text{A}

Step-by-step solution

VA−VB=4−(−6)=10{V}_{A} - {V}_{B} = 4 - \left(- 6\right) = 10

∴i=101000=10−2A∴ i = \dfrac{10}{1000} = {10}^{- 2}A
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