Here, output
C=(A¯+B¯) \cdot \left(A + \overset{¯}{B}\right)</p><p>Thetruthtableforthegivenlogiccircuitis
| A</td><td>B</td><td>\overset{¯}{A}</td><td>\overset{¯}{B}</td><td>(A¯+B¯) | \left(A + \overset{¯}{B}\right)</td><td>C</td></tr><tr><td>0</td><td>0</td><td>1</td><td>1</td><td>1 | 1 | 1 |
| 0 | 1 | 1 | 0 | 1</td><td>0</td><td>0</td></tr><tr><td>1</td><td>0</td><td>0</td><td>1</td><td>1</td><td>1 | 1 |
| 1 | 1 | 0 | 0 | 0 | 1 | 0 |
