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NEET2016PhysicsSemiconductorsActual

A NPN transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800   Ω is connected in the collector circuit and the voltage drop across it is 0 .8 V . If the current amplification factor is 0.96 and the input resistance of the circuit is 192   Ω , the voltage gain and the power gain of the amplifier will respectively be:

Options

  1. A4 ,   3.84
  2. B3.69 ,   3.84
  3. C4 ,   4
  4. D4 ,   3.96

Correct answer

A. 4 ,   3.84

Step-by-step solution

Given, The value of the load resistance is 800   Ω . Voltage drop across the load resistance is, 0 . 8   V Voltage gain = β . R C R B V = 0.96 80 192 V = 96 × 8 192 = 4 And power gain of the amplifier is given by, β a c . A v = 0.96 × 4 = 3.84

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