A NPN transistor is connected in common emitter configuration in a...

Given,

The value of the load resistance is $800Ω$.

Voltage drop across the load resistance is, $0 . 8V$

Voltage gain $= \beta . \left(\dfrac{{R}_{C}}{{R}_{B}}\right)$

$V = 0.96\left(\dfrac{80}{192}\right)$

$V = \dfrac{96 \times 8}{192} = 4$

And power gain of the amplifier is given by,

${\beta}_{ac} . {A}_{v}$

$= 0.96 \times 4$

$= 3.84$