A transistor is operated in common emitter configuration at V_C=2 ~V such that a change in the base current from 100 μ A to 300 μ A produces a change in the collector current from 10 ~mA to 20 ~mA . The current gain is

Correct answer: D. 50 β=(Δ I_C)/(Δ I_B)= (20-10) mA (300-100) mA = 10 × 10^ -3 200 × 10^ -6 =50

NEET 2011

NEET 2011 · Physics · Semiconductors

A transistor is operated in common emitter configuration at V_C=2...

A transistor is operated in common emitter configuration at

V_C=2 \mathrm{~V}

such that a change in the base current from

100 \mu \mathrm{A}

300 \mu \mathrm{A}

produces a change in the collector current from

10 \mathrm{~mA}

20 \mathrm{~mA}

. The current gain is

D. 50

\beta=\frac{\Delta I_C}{\Delta I_B}=\frac{(20-10) \mathrm{mA}}{(300-100) \mathrm{mA}}=\frac{10 \times 10^{-3}}{200 \times 10^{-6}}=50