A transistor is operated in common-emitter configuration at V_c=2 volt such that a change in the base current from 100 μ A to 200 μ A produces a change in the collector current from 5 ~mA to 10 ~mA . The current gain is

Correct answer: D. 50 For a transistor aligned & where array l I_ E =I_ B +I_ C I_ E = emitter current I_ B = base current I_ C = collector current and current gain β= Δ I_ C Δ I_ B Δ I_ C =5 ×10^ -3 ~A Δ I_ B =100 ×10^ -6 ~A β=(5)/(100) ×1000=50 array aligned

NEET 2009

Exam: NEET
Year: 2009
Subject: Physics
Chapter: Semiconductors

NEET 2009 · Physics · Semiconductors

A transistor is operated in common-emitter configuration at V_c=2...

A transistor is operated in common-emitter configuration at

V_c=2

volt such that a change in the base current from

100 \mu \mathrm{A}

200 \mu \mathrm{A}

produces a change in the collector current from

5 \mathrm{~mA}

10 \mathrm{~mA}

. The current gain is

Options

A75
B100
C150
D50

Correct answer

D. 50

Step-by-step solution

For a transistor

\begin{aligned}& \text{ where } \quad \begin{array}{l} \mathrm{I}_{\mathrm{E}}=\mathrm{I}_{\mathrm{B}}+\mathrm{I}_{\mathrm{C}}\\ \mathrm{I}_{\mathrm{E}}=\text{ emitter current }\\ \mathrm{I}_{\mathrm{B}}=\text{ base current }\\ \mathrm{I}_{\mathrm{C}}=\text{ collector current }\\ \text{ and current gain } \beta=\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}}\\ \Delta \mathrm{I}_{\mathrm{C}}=5 \times10^{-3} \mathrm{~A}\\ \Delta \mathrm{I}_{\mathrm{B}}=100 \times10^{-6} \mathrm{~A}\\ \beta=\frac{5}{100} \times1000=50 \end{array} \end{aligned}

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