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NEET 2013
Exam
NEET
Year
2013
Subject
Physics
Chapter
Semiconductors

NEET 2013 · Physics · Semiconductors

In a common emitter (CE) amplifier having a voltage gain G , the...

In a common emitter (CE) amplifier having a voltage gain GG, the transistor used has transconductance 0.03 mho and current gain 25. If the above transistor is replaced with another one with transconductance 0.02mho0.02 \mathrm{mho} and current gain 20 , the voltage gain will

Options

  1. A23G\frac{2}{3} G
  2. B1.5G1.5 \mathrm{G}
  3. C13G\frac{1}{3} G
  4. D54G\frac{5}{4} G

Correct answer

A. 23G\frac{2}{3} G

Step-by-step solution

\mathrm{As} A_v=\beta \frac{R_L}{R_j} \quad \left[\because g_m=\frac{\Delta_C}{\Delta V_B}=\frac{\Delta_C}{\Delta /_B R_j}\right] or G=(βRi)RL[∵gm=βRi]G=\left(\frac{\beta}{R_i}\right) R_L \quad\left[\because g_m=\frac{\beta}{R_i}\right]⇒G=gmRi⇒G∝gm\begin{array}{ll} \Rightarrow & G=g_m R_i \\ \Rightarrow & G \propto g_m \end{array}∴G2G1=gm1gm2⇒G2=0.020.03×G∴ Voltage gain G2=23G\begin{aligned}& \therefore \quad \frac{G_2}{G_1}=\frac{g_{m_1}}{g_{m_2}}\\ & \Rightarrow \quad G_2=\frac{0.02}{0.03} \times G \\ & \therefore \text{ Voltage gain } G_2=\frac{2}{3} G\end{aligned}$
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