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Identify Z in the sequence, CH 3 CH 2 CH = CH 2 → HBr / H 2 O 2 Y ⁡ → C 2 H 5 ONa Z

Options

  1. AH | H 3 C − C − O − CH 2 − CH 3 | H
  2. BCH 3 - CH 2 - CH CH 3 | - O - CH 2 - CH 3
  3. CCH 3 - (CH 2 ) 3 - O - CH 2 - CH 3
  4. DCH 3 - (CH 2 ) 4 - O - CH 3

Correct answer

C. CH 3 - (CH 2 ) 3 - O - CH 2 - CH 3

Step-by-step solution

CH 3 CH 2 CH = CH 2 → HBr / H 2 O 2 CH 3 CH 2 CH 2 CH 2 Br → C 2 H 5 ONa CH 3 CH 2 3 OC 2 H 5 In presence of H 2 O 2 , HBr adds as per anti-Markownikoff's way (peroxide effect). CH 3 CH 2 CH 2 CH 2 Br + NaOC 2 H 5 → -NaBr CH 3 (CH 2 ) 3 -O-C 2 H 5

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