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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Carboxylic Acid Derivatives

NTA Abhyas 2020 · Chemistry · Carboxylic Acid Derivatives

In the given reaction C H _ 3 - C H _ 2 COOH (i)C H _ 3...

In the given reaction

CH3−CH2COOH→(i)CH3Li(excess)(ii)H3O⊕[X]C{H}_{3} - C{H}_{2}COOH\overset{\left(i\right)\text{C}{\text{H}}_{3}Li\left(\text{excess}\right)\left(ii\right){\text{H}}_{3}{O}^{⊕}}{\to}\left[X\right]

[X] will beIn the given reaction C H _ 3 - C H _ 2 COOH (i)C H _ 3 Li(excess)(ii) H _ 3 O ^ ⊕ → [X] [X] will be

Options

  1. ACH3−CH2COOLiC{H}_{3} - C{H}_{2}COOLi
  2. BCH3−CH2−C∣∣O−CH3C{H}_{3} - C{H}_{2} - \overset{O}{\overset{| |}{C}} - C{H}_{3}
  3. CCH3−CH2−CH2OHC{H}_{3} - C{H}_{2} - C{H}_{2}OH
  4. DCH3−CH2−CH2−CH3C{H}_{3} - C{H}_{2} - C{H}_{2} - C{H}_{3}

Correct answer

B. CH3−CH2−C∣∣O−CH3C{H}_{3} - C{H}_{2} - \overset{O}{\overset{| |}{C}} - C{H}_{3}

Step-by-step solution

In the given reaction C H _ 3 - C H _ 2 COOH (i)C H _ 3 Li(excess)(ii) H _ 3 O ^ ⊕ → [X] [X] will be
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