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At 500 K , the half life period of a gaseous reaction at an initial pressure of 80 k P a is 350 s . When the pressure is 40 k P a , the half life period is 175 s e c ; the order of the reaction is :

Options

  1. Azero
  2. Bone
  3. Ctwo
  4. Dthree

Correct answer

A. zero

Step-by-step solution

( T 1 2 T 1 2 ) = ( C 1 C 2 ) 1 − n ⇒ ( 350 175 ) = ( 80 40 ) 1 − n = 2 = ( 2 ) 1 − n ⇒ 1 − n = 1 ⇒ n = 0

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