NTA Abhyas JEE Main2020ChemistryChemical KineticsPractice
The radioactive isotope 90 234 Th undergoes two successive β - decay followed by α decay. The atomic number and the mass number respectively of the resulting isotope are
Options
- A92 and 237
- B94 and 230
- C90 and 230
- D92 and 230
Correct answer
C. 90 and 230
Step-by-step solution
9 0 Th 2 3 4 ⟶ - 2 β 9 2 Χ 2 3 4 ⟶ - α 9 0 Th 2 3 0 Elimination of 1 α and 2 β particles give isotope.