NTA Abhyas JEE Main2020ChemistryChemical KineticsPractice
Find the rate law that corresponds to the data shown for the following reaction? Experiment Al 0 = M [ B ] 0 = M Initial rate 1 0 . 012 0 . 035 0 . 10 2 0 . 024 0 . 070 0 . 80 3 0 . 024 0 . 035 0 . 10 4 0 . 012 0 . 070 0 . 80
Options
- ARate = k [ A ] 0 [ B ] 3
- BRate = k [ B ] 4
- CRate = k [ A ] [ B ] 3
- DRate = k A 2 [ B ] 2
Correct answer
A. Rate = k [ A ] 0 [ B ] 3
Step-by-step solution
 Expt.  4  Expt.  1 = [ 0 . 012 ] x [ 0 . 070 ] y [ 0 . 012 ] x [ 0 . 035 ] y = 0 . 80 0 . 10 2 y = 8 ∴ y = 3  Expt.  3  Expt.  1 = [ 0 . 024 ] x [ 0 . 035 ] 3 [ 0 . 012 ] x [ 0 . 035 ] 3 = 0 . 10 0 . 10 2 x = 1    x = 0 Rate = k [ A ] 0 [ B ] 3 .