NTA Abhyas JEE Main2020ChemistryChemical KineticsPractice
For the reaction mechanism of the reaction 2 NO(g) + 2 H 2 (g) → N 2 (g) + 2 H 2 O(g) . Step I 2 NO ⇌ k 1 N 2 O 2 ; K eq fast Step II N 2 O 2 +H 2 → k 2 N 2 O+H 2 O slow Step III N 2 O+H 2 → k 3 N 2 +H 2 O fast Expression of rate of reaction is (Take K eq × k 2 = k')
Options
- Ak' [NO] 2 [H 2 ]
- Bk' N 2 O 2 [H 2 ]
- Ck' N 2 O [H 2 ]
- Dk' N 2 O 2
Correct answer
A. k' [NO] 2 [H 2 ]
Step-by-step solution
Step I 2 NO ⇌ k 1 N 2 O 2 ; K eq fast Step II N 2 O 2 + H 2 ⟶ k 2 N 2 O + H 2 O slow Step III N 2 O + H 2 ⟶ k 3 N 2 + H 2 O fast (i) Derive the rate Law Rate = k 2 N 2 O 2 H 2 (Rate determining step) N 2 O 2 NO 2 = K eq ∴ N 2 O 2 = K eq NO 2 Rate = k 2 K eq NO 2 H 2 k' NO 2 H 2 Rate law is third order