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Consider the following gaseous reaction where initial pressure of A(g) is 200 torr A(g) → 3B(g) + C(g) After time t, the pressure of system increased to 650 torr . Calculate the value of t (in seconds) (Given: rate constant of reaction, k = 4 .606 × 10 − 3 sec − 1 , log 2 = 0 .3 )

Options

  1. A600
  2. B300
  3. C50
  4. D5

Correct answer

B. 300

Step-by-step solution

200 − p + 3p + p = 650 p =150 torr t = 1 k × 2.303 × log ⁡ 200 200 - p = 1 × 2 .303 ×log 4 4 .606 × 10 − 3 = 300 sec

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