NTA Abhyas JEE Main2020ChemistryChemical KineticsPractice
For reactions P → Q and X → Y Arrhenius constants are 1 0 6 and 1 0 8 respectively. If E P → Q = 1500 c a l / m o l e and E x → y = 2000 c a l / m o l e , then find the temperature at which their rate constants are same. ( G i v e n : R = 2 c a l / m o l e / K )
Options
- A500 K
- B250 × 4.606 K
- C250 4.606 K
- D4.606 250 K
Correct answer
C. 250 4.606 K
Step-by-step solution
A 1 e - E a 1 / R T = A 2 e - E a 2 / R T A 2 A1 = e E a 2 - E a 1 / R T 1 0 2 = e 500 / R T R = 2 c a l / K / m o l e 2 l n 10 = 500 2 T T = 250 2 × 2.303 K