NTA Abhyas JEE Main2020ChemistryChemical KineticsPractice
The reaction X + Y → Z is first order with respect to X and second order with respect to Y , initial rate of formation of Z = R mol dm 3 sec − 1 when [X] and [Y] are 0 .40 mol dm − 3 and 0 .30 mol dm − 3 respectively. If [X] is halved and [Y] is doubled, the value of the initial rate would become
Options
- A4 R
- BR 4
- CR
- D2 R
Correct answer
D. 2 R
Step-by-step solution
X + Y → Z R a t e 1 = K X Y 2 R a t e 2 = K X 2 2 Y 2 R a t e 1 R a t e 2 = 1 2 R a t e 2 = 2 R a t e 1 = 2 R