For the reaction: 3 A ( g ⁡ ) → 2 B ( g ⁡ ) , the rate of formation of ' B ' at 298   K is represented as ln d B dt   =   − 4 .606   +   2   ln   A   . The order of reaction is

Step-by-step solution

ln ⁡ d B d t = - 4.606 + 2 ln ⁡ [ A ] 2.303 log d B dt = − 4.606 + 2 × 2.303 log A log d B dt = − 4.606 2.303 + 2 log A log d B dt = − 2 + 2 log A log d B dt = log 10 − 2 + log A 2 log d B dt = log 10 − 2 A 2 d B d t = 1 0 - 2 A 2 Compare with d B d t = k A m d B d t = 1 0 - 2 A 2 Order = 2