NTA Abhyas JEE Main2020ChemistryChemical KineticsPractice
Half-life period of the radioactive element A is 10 days. Amount of A left on the end of 11th day starting with 1 mole A is 1 2 n + 6 10 mole. What is the value of n.
Correct answer
5
Step-by-step solution
A t = A 0 × 1 2 n o o f h a l f l i f e 1 2 n + 6 10 = 1 2 11 10 n = 5