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An organic compound undergoes first order decomposition. The time taken for its decomposition to 1 8 and 1 10 of its initial concentration are t 1 8 and t 1 10 respectively. What is the value of t 1 8 t 1 10 × 10 ? (take lo g 10 2 = 0.3 )

Correct answer

9

Step-by-step solution

As we know k t = ln ⁡ A 0 A t t 1 8 t 1 10 = ln ⁡ 8 ln ⁡ 1 0 = 0.9 t 1 8 t 1 10 × 10 = 9

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