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Consider the reaction A → 2 B + C, Δ H = - 1 5 kcal . The energy of activation of backward reaction is 20 kcal mol -1 . In presence of catalyst, the energy of activation of forward reaction is 3 kcal mol -1 . At 400 K the catalyst causes the rate of the forward reaction to increase by the number of times equal to-

Options

  1. Ae 3.5
  2. Be 2.5
  3. Ce -2.5
  4. De 2.303

Correct answer

B. e 2.5

Step-by-step solution

E a f - E a b = Δ H = - 1 5 kcal ⇒ E a f = - 1 5 + 2 0 = 5 kcal k catalyst k a = e E a - E a catalyst / RT = e 5 - 3 × 1 0 3 / 2 × 4 0 0 = e 2 . 5

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