NTA Abhyas JEE Main2020ChemistryChemical KineticsPractice
The experimental data for the reaction, 2 A + B 2 → 2 A B is The rate equation for the above data is
Options
- ARate = k A 2 B 2
- BRate = k A 2 B
- CRate = k B 2
- DRate = k B 2 2
Correct answer
C. Rate = k B 2
Step-by-step solution
For the reaction 2 A + B 2 ⇌ 2 A B , Rate ∝ [ A ] x [ B 2 ] y . On substituting the given data, we get From experimental 1, 1.6 × 1 0 - 4 ∝ 0.50 x 0.50 y ...(i) From experimental 2, 3.2 × 1 0 - 4 ∝ 0.50 x 1.00 y ...(ii) From experimental 3, 3.2 × 1 0 - 4 ∝ 1.00 x 1.00 y ...(iii) 1 = 1.00 0.50 x or 1 = 2 x or 2 0 = 2 x or x = 0 Now, divide equation (ii) by equation (i) we get, 2 = 1.00 0.50 y 2 = 2 y y = 1 Thus rate equation is: Rate = k A 0 B 2 1 = k B 2 .