NTA Abhyas JEE Main2020ChemistryChemical KineticsPractice
For a first order reaction A → P , the temperature (T) dependent rate constant k was found to follow the equation log k = - 2000 1 T + 6.0 . The pre-exponential factor A and the activation energy E a , respectively, are
Options
- A1.0 × 10 6 s - 1 and 9.2 kJ mol - 1
- B6.0 s - 1 and 16.6 kJ mol - 1
- C1.0 × 10 6 s - 1 and 16.6 kJ mol - 1
- D1.0 × 10 6 s - 1 and 38.3 kJ mol - 1
Correct answer
D. 1.0 × 10 6 s - 1 and 38.3 kJ mol - 1
Step-by-step solution
log k = log A − E a 2.303 R T ...(1) Also given log k = 6.0 − ( 2000 ) 1 T …(2) On comparing equations, (1) and (2) log A = 6.0 ⇒ A = 10 6 s − 1 and E a 2.303 R = 2000 ; ⇒ E a = 2000 × 2.303 × 8.314 = 38.29 kJ mol − 1