NTA Abhyas JEE Main2020ChemistryChemical KineticsPractice
For a certain reaction the variation of rate constant with temperature is given by the equation l n k t = l n k 0 + l n 3 t 10 t ≥ 0 ° C where k 0 =k at zero degree centigrade The value of temperature coefficient of the reaction is -
Options
- A0.1
- B1
- C10
- D3
Correct answer
D. 3
Step-by-step solution
The variation of 'k' with 'T' is given by k T   =   k 0 μ t 10 where μ is temperature coefficient ∴   ln   k T   =   ln   k 0 + t 10 ln   μ comparing with given eq n we get μ   =   3