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The following data were obtained during the first order thermal decomposition of S O 2 C l 2 at a constant volume. S O 2 C l 2 g → S O 2 g + C l 2 g Experiment Time / s - 1 Total pressure/atm 1 0 0.5 2 100 0.6 What is the rate of reaction when total pressure is 0.65 atm?

Options

  1. A0.35 atm s - 1
  2. B2.235 × 1 0 - 3 atm s - 1
  3. C7.8 × 1 0 - 4 atm s - 1
  4. D1.55 × 1 0 - 4 atm s - 1

Correct answer

C. 7.8 × 1 0 - 4 atm s - 1

Step-by-step solution

S O 2 C l 2 g → S O 2 g + C l 2 g k = 2.303 t log ⁡ p 0 2 p 0 - P t = 2.303 100 log ⁡ 0.5 2 × 0.5 - 0.6 = 2.303 100 log ⁡ 1 . 25 = 2.2318 × 1 0 - 3 s - 1 Pressure of S O 2 C l 2 at time t p S O 2 C l 2 = 2 p 0 - P t = 2 × 0.50 - 0.65 atm = 0.35 atm Rate of that time = k × p S O 2 C l 2 = 2.2318 × 1 0 - 3 × 0.35 = 7.8 × 1 0 - 4 atm s - 1

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