NTA Abhyas JEE Main2020ChemistryChemical KineticsPractice
When a plot between logk and 1/T is plotted we get the graph as shown. What is the value of slope in the graph?
Options
- AE a R T
- B- E a 2.303 R
- C- E a 2.303 R T log A
- D- E a 2.303 R T
Correct answer
B. - E a 2.303 R
Step-by-step solution
log k = log A - E a 2.303 R 1 T log k = - E a 2.303 R T + log A Slope = - E a 2.303 R