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For the reaction 2 N 2 O 5 → 4 N O 2 + O 2 , rate and rate constant are 1.02 × 10 – 4 mol lit – 1 sec – 1 ⁡ and 3.4 × 10 – 5 sec – 1 ⁡ respectively then concentration of N 2 O 5 at that time will be

Options

  1. A1.732 M
  2. B3 M
  3. C3.4 × 10 5 M
  4. D1.02 × 10 – 1 M

Correct answer

B. 3 M

Step-by-step solution

2 N 2 O 5 → 4 N O 2 + O 2 From the unit of rate constant it is clear that the reaction follow first order kinetics. Hence by rate law equation, r = k [ N 2 O 5 ] Where r = 1.02 × 10 − 4 , k = 3.4 × 10 − 5 1.02 × 10 − 4 = 3.4 × 10 − 5 [ N 2 O 5 ] [ N 2 O 5 ] = 3 M

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