NTA Abhyas JEE Main2020ChemistryChemical KineticsPractice

For the equilibrium, A g ⇌ B g , ∆ H is - 40 kJ/mol. If the ratio of the activation energies of the forward E f and reverse E b reactions is 2 3 then:

Options

AE f = 30 kJ/mol, E b = 70 kJ/mol
BE f = 70 kJ/mol, E b = 30 kJ/mol
CE f = 80 kJ/mol, E b = 120 kJ/mol
DE f = 60 kJ/mol, E b = 100 kJ/mol

Correct answer

C. E f = 80 kJ/mol, E b = 120 kJ/mol

Step-by-step solution

A g ⇌ B g ; ∆ H = - 40 kJ/mole ∆ H = E a f - E a b = - 40 k J E a f E a b = 2 3 ⇒ E a f = 2 3 E a b ⇒ 2 3 E a b - E a b = - E a b 3 = - 40 k J E a b = + 120 k J E a f = 2 3 × 120 = 80 k J

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