NTA Abhyas JEE Main2020ChemistryChemical KineticsPractice
For given first order reaction, the reactant reduces to 1/4th its initial value in 10 min. The rate constant of the reaction is
Options
- A0.1386 mi n - 1
- B0.0693 mi n - 1
- C0.1386 mol L - 1 min - 1
- D0.0693 mol L - 1 min - 1
Correct answer
A. 0.1386 mi n - 1
Step-by-step solution
For the first order reaction, k = 2.303 t log a a - x Given, t = 10 min a = a a - x = a 4 k = 2.303 10 log a a 4 = 2.303 × 2 10 log 2 = 0.1386 mi n - 1