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A reaction is first order in A and second order in B : How is the rate affected when the concentrations of both A and B are doubled ?

Options

  1. ARate of reaction becomes 6 times
  2. BRate of reaction becomes 8 times
  3. CRate of reaction becomes 10 times
  4. DRate of reaction becomes 4 times

Correct answer

B. Rate of reaction becomes 8 times

Step-by-step solution

Rate = k[2A] [2B] 2 = 8k[A] [B] 2 Rate of reaction becomes 8 times

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