NTA Abhyas JEE Main2020ChemistryChemical KineticsPractice
A reactant A forms two products A → k 1 B; Activation energy E a 1 A → k 2 C; Activation energy E a 2 If E a 2 = 2 E a 1 , then k 1 and k 2 will be related as
Options
- Ak 2 = k 1 e − E a 1 RT
- Bk 2 = k 1 e E a 2 R T
- Ck 1 = A k 2 e E a 1 R T
- Dk 1 = 2 k 2 e E a 2 R T
Correct answer
A. k 2 = k 1 e − E a 1 RT
Step-by-step solution
k 2 = A e - E a 2 R T , k 1 = A e - E a 1 R T So, k 2 k 1 = e − 2E a 1 +E a 1 RT Since, E a 2 = 2 E a 1 k 2   =   k 1 e − E a 1 RT