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A graph plotted between log k versus 1/T for calculating activation energy is shown by

Correct answer

1

Step-by-step solution

k = A e - E a / R T log e ⁡ k = log e ⁡ A - E a R T log 10 ⁡ k = log 10 ⁡ A - E a 2.303 R × 1 T y = m x + C Plot of log k against 1/T will give straight line with negative slope.

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