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For the given reaction 2 N 2 O 5 → 4 N O 2 + O 2 , the rate of reaction and rate constant values are 1.02 × 1 0 - 4 and 3.4 × 1 0 - 5 se c - 1 respectively. Then calculate the concentration of N 2 O 5 at that time

Options

  1. A1.732
  2. B3
  3. C1.02 × 1 0 - 4
  4. D3.4 × 1 0 5

Correct answer

B. 3

Step-by-step solution

The unit of rate constant suggest that it is a first order reaction. Hence the given rate law is R = K [ A ] , 1.02 × 1 0 - 4 = 3.4 × 1 0 - 5 × [ N 2 O 5 ] or N 2 O 5 = 1.02 × 1 0 - 4 3.4 × 1 0 - 5 = 3

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