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NTA Abhyas JEE Main2020ChemistryChemical KineticsPractice

Which of the following is/are correct for the first order reaction?

Options

  1. AI, II
  2. BII, III
  3. CI, II III
  4. DI, III

Correct answer

A. I, II

Step-by-step solution

I. log ( a – x ) , where ( a – x ) is remaining concentration, decreases with passage of time. log a − x = log a − kt 2 .303 y = log a − k 2 .3030 x slope = − ve II. k = 2.303 t log 10 ⁡ a a - x log a a - x = k 2 .303 × t = y = k 2 . 303 x y = m × x Plot of log ⁡ a a - x against 't' gives straight line through origin. III. t 1 / 2 = 0.693 k ; Half-life of first order reaction does not depend on initial concentration. Thus, graph of t 1 / 2 against 'a' gives horizontal straight line.

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