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Formation of ammonia is given by the elementary reaction N 2 + 3 H 2 → 2 N H 3 . If the rate of formation of ammonia is Δ N H 3 Δ t = 4 × 1 0 - 4 m o l l - 1 s - 1 , then calculate value of - Δ H 2 Δ t

Options

  1. A3 × 1 0 - 4 m o l l - 1 s - 1
  2. B4 × 1 0 - 4 m o l l - 1 s - 1
  3. C6 × 1 0 - 4 m o l l - 1 s - 1
  4. D6.5 × 1 0 - 4 m o l l - 1 s - 1

Correct answer

C. 6 × 1 0 - 4 m o l l - 1 s - 1

Step-by-step solution

N 2 + 3 H 2 ⇌ 2 N H 3 - Δ N 2 Δ t = - 1 3 Δ H 2 Δ t = 1 2 Δ N H 3 Δ t ∴ - Δ H 2 Δ t = 3 2 × Δ N H 3 Δ t = 3 2 × 4 × 1 0 - 4 = 6 × 1 0 - 4 m o l l i t r e - 1 s e c - 1

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