NTA Abhyas JEE Main2020Chemistryd and f Block ElementsPractice
X + K 2 C O 3 + A i r → h e a t Y Y + C l 2 → Z P u r p l e Which of the following is correct?
Options
- AX = black, M n O 2 , Y = Blue, K 2 C r O 4 , Z = K M n O 4
- BX = green, C r 2 O 3 , Y = Yellow, K 2 C r O 4 , Z = K 2 C r 2 O 7
- CX = black, M n O 2 , Y = green, K 2 M n O 4 , Z = K M n O 4
- DX = black; B i 2 O 3 , Y = colourless K B i O 2 , Z = K B i O 3
Correct answer
C. X = black, M n O 2 , Y = green, K 2 M n O 4 , Z = K M n O 4
Step-by-step solution
2MnO 2 X +   2K 2 CO 3   +   O 2 air → Δ 2K 2 MnO 4 green Y   +   2CO 2 ↑ 2 K 2 M n O 4 Y + C l 2 → 2 K M n O 4 Z P u r p l e + 2 K C l