NTA Abhyas JEE Main2020Chemistryd and f Block ElementsPractice
X + K 2 C O 3 + A i r → h e a t Y Y + C l 2 → Z P i n k Which of the following is correct?
Options
- AX = b l a c k , M n O 2 , Y = B l u e , K 2 C r O 4 , Z = K M n O 4
- BX = g r e e n , C r 2 O 3 , Y = Y e l l o w , K 2 C r O 4 , Z = K 2 C r 2 O 7
- CX = b l a c k , M n O 2 , Y = g r e e n , K 2 M n O 4 , Z = K M n O 4
- DX = b l a c k ; B i 2 O 3 , Y = c o l o u r l e s s K B i O 2 , Z = K B i O 3
Correct answer
C. X = b l a c k , M n O 2 , Y = g r e e n , K 2 M n O 4 , Z = K M n O 4
Step-by-step solution
Here X = b l a c k , M n O 2 , Y = g r e e n , K 2 M n O 4 , Z = K M n O 4