NTA Abhyas JEE Main2020Chemistryp Block Elements (Group 13 & 14)Practice
The intermediate product (X) formed in the following reaction is B 2 H 6 + 6 N H 3 → 3 X → h e a t 2 B 3 N 3 H 6 + 12 H 2
Options
- AB H N H 3 3 + B H 4 -
- BB H 2 N H 3 4 + B H 4 -
- CB H N H 3 4 + B H 4 -
- DB H 2 N H 3 2 + B H 4 -
Correct answer
D. B H 2 N H 3 2 + B H 4 -
Step-by-step solution
3 B 2 H 6 D i b o r a n e + 6 N H 3 → l o w temp. 3 B H 2 N H 3 2 + B H 4 - ( X ) → 473 K Δ 2 B 3 N 3 H 6 B o r a z i n e + 12 H 2