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How many unit cells are present in a cube shaped ideal crystal of NaCl of mass 1 .00 g ?

Options

  1. A2 . 5 7 × 1 0 2 1
  2. B5 . 1 4 × 1 0 2 1
  3. C1 . 2 8 × 1 0 2 1
  4. D1 . 7 1 × 1 0 2 1

Correct answer

A. 2 . 5 7 × 1 0 2 1

Step-by-step solution

∴ Mass of one unit cell = V × d (V is volume, d is density) = a 3 × d Also, density = z × at. wt. a 3 × av. no. ∴ Mass of one unit cell = a 3 × z × at. wt. a 3 × av. no. = z × at. wt. av. no. = 4 × 5 8 . 5 6 . 0 2 × 1 0 2 3 (z = 4 for cubic shape) = 3 8 . 8 7 × 1 0 - 2 3 g ∴ No. of unit cell in 1 g = 1 3 8 . 8 7 × 1 0 - 2 3 = 2 . 5 7 × 1 0 2 1

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